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$ dy ~=~ r db $ $ dy ~=~ r ~ db $
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For circular orbital motion, $ ~ a ~=~ v^2 / r ~ $, so $ v^2 ~ = ~ 2 \mu \lambda $

Therefore, for an infinite line mass, '''rotation velocity is constant, regardless of radius.'''

And this matches galactic rotation curves, for example:

{{ https://proxy.duckduckgo.com/iu/?u=https%3A%2F%2Ftse4.mm.bing.net%2Fth%3Fid%3DOIP.QQ7frcHy7fWljgM6SuO0OAHaF2%26pid%3D15.1&f=1 }}

Cold Dark Matter

New Scientist 2017 11 October

Hideki Tanimura at the Institute of Space Astrophysics in Orsay, France

Anna de Graaff at the University of Edinburgh, UK.

There may be no exotic dark matter, just gas that is very difficult to detect without large, sensitive instruments in space. Planck can only image some of this "dim" matter by overlaying hundreds of images, which cannot detect other baryons (mostly protons) that are not clustered this way.

Rotation Curves around a Line Mass

"Heavy" line mass filaments perpendicular to a galaxy produce rotation curves with constant velocity at any radius.

Standard Gravitational Constant

\lambda

line mass density, i.e., kg/m

r

radius of body from line mass

y

vertical offset from mass element

l = \sqrt{ r^2 + y^2 }

distance from mass element

b

integration substitution variable

a

acceleration towards line mass

v

orbital velocity around line mass

da ~=~ gravity \times cos( angle )

da ~=~ \Large { { \mu \lambda dy } \over { l^2 } } { r \over l }

a ~=~ \mu \lambda r \Large \int_{-\infty}^{+\infty} { dy \over l^3 }

substitute y = b r :

dy ~=~ r ~ db

l ~=~ \sqrt{ r^2 + y^2 } = \sqrt{ r^2 + b^2 r^2 } = r \sqrt{ 1 + b^2 }

a ~=~ \mu \lambda r \Large \int_{-\infty}^{+\infty} { r db \over { r^3 ( 1 + b^2 )^{3/2} } }

a ~=~ \Large { { \mu \lambda } \over r } \int_{-\infty}^{+\infty} { db \over { ( 1 + b^2 )^{3/2} } }

a ~=~ \Large { { 2 \mu \lambda } \over r }

For circular orbital motion, ~ a ~=~ v^2 / r ~ , so v^2 ~ = ~ 2 \mu \lambda

Therefore, for an infinite line mass, rotation velocity is constant, regardless of radius.

And this matches galactic rotation curves, for example:

https://proxy.duckduckgo.com/iu/?u=https://tse4.mm.bing.net/th?id=OIP.QQ7frcHy7fWljgM6SuO0OAHaF2&pid=15.1&f=1

ColdDarkMatter (last edited 2018-12-10 07:58:31 by KeithLofstrom)