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== Light Pressure Modified Orbits == = Light Pressure Modified Orbits =
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Solar light pressure is useful for maneuvering, but it distorts orbits. Light pressure slows objects orbiting towards the sun, and speeds up objects orbiting away from it. This raises and lowers portions of the orbit. A slightly elliptical orbit with perigee towards the sun will rotate. With proper matching of eccentricity, the apogee and perigee will complete one rotation per year. Light pressure effects modify server-sat array orbits. In the nominal orbit, server-sats are at "half thrust", with each thruster half mirror and half transparent. Variations to full or zero reflectivity, and full or zero thrust, allow each server-sat to maneuver in relation to the array, or for the array as a whole to maneuver around its assigned centerpoint. The following is an analysis of two effects, earth oblateness and nominal half-thrust light pressure, on the orbit. We will assume that the arrays maintain a constant, slightly elliptical orbit that precesses once per year in the equatorial plane. We will assume continuous illumination tangential to the equatorial plane, and zero light pressure effects from Earth albedo or black-body radiation, and no solar or lunar tides. These assumptions are somewhat crude approximations to get us into the ballpark of a solution. Precise solutions will probably demand accurate numerical solutions simulating many years of orbital evolution.
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'''This section does not include the effects of the Earth's oblateness, albedo, and black body radiation, nor the eclipse of the sun once per orbit, effects having similar magnitude to the solar light pressure. The final target orbit will be significantly different than the one discussed here.''' == Earth Oblateness ==
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{{attachment:nav_eastwest.png|orbit from the north}}
An orbit can be viewed in a rotating frame of reference centered on a point in circular orbit. For small eccentricities, an elliptical orbit traces a circle in this frame, rotating in the opposite direction from the orbit itself. That is, if the orbit is eastwards, rotating counterclockwise when viewed from the north, the orbit rotates clockwise in the rotating frame. If the frame is positioned with the earth below, the top of the circle is the apogee and the bottom of the circle is the perigee, so the orbit moves backwards (to the right) compared to the "circular center" at apogee (more slowly), and forwards (to the left) at perigee (more rapidly).
For "heavy" server-sats relatively close to the earth, such as 3 gram satellites at m288, the dominant deviation from a perfect Kepler orbit is caused by the $ J_2 $ spherical harmonic of the gravity field, in turn caused by the oblateness of the spinning Earth. For small eccentricities, the eastward precession of the perigee of one elliptical equatorial orbit is proportional to the $ J_2 $ term of the WGS84 model ( -1.082626683E-03 , see Pisacane 2008 ) and the inverse of the orbit radius squared. The precession, expressed as the number complete precessions per year, is $ J \approx -3 J_2 ( Y / P ) ( R_e / R_s ) ^ 2 ~ ~ $ where
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An elliptical orbit is distorted from a circular one by the distance between the focii of the ellipse.
The distance from the center to each focus, or the eccentricity times the semimajor axis,
is called the ''linear eccentricity'' of the ellipse, or $ \epsilon r_0 $.
The linear eccentricity is the radius of the orbit circle in the rotating frame.
||$ J $ ||precessions per year caused by oblateness, ||
||$ J_2 $ ||spherical harmonic of gravity causing oblateness,||
|| $ Y $ ||year period in seconds, ||
||$ P $ ||orbit period in seconds, ||
||$ Y/P $ ||number of orbits per year, ||
||$ R_e $ ||earth equatorial radius = 6378km, ||
||$ R_s $ ||orbit equatorial radius. ||
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If the orbit precesses once per year, then the vector of the linear eccentricity makes one complete rotation per year.
Each orbit adds a little bit of rotation to that vector.
|| orbit || radius (RE) || orbits/year || J ||
|| LEO || 1.047 || 5758.5 || 17.061 ||
|| m288 || 2.005 || 2191.5 || 1.771 ||
|| m360 || 2.264 || 1826.2 || 1.157 ||
|| m480 || 2.627 || 1461.0 || 0.688 ||
|| m720 || 3.182 || 1095.7 || 0.351 ||
|| m1440 || 4.168 || 730.5 || 0.137 ||
|| GEO || 6.611 || 365.2 || 0.027 ||
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Viewed closely, the displacement caused by light pressure looks like a cycloid ruffle on the orbit circle.
In the rotating frame of reference, the sun appears to rotate around the orbit circle once per orbit period,
 with the light pressure acceleration pointing away from the sun.
The sun "disappears" during the eclipsed part of the orbit,
 and this changes the math somewhat,
but the major effects are caused when the object is moving towards or away from the sun, on the sides of the ellipse.
This rough estimate ignores eclipses.
== Server Satellite data ==
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Referenced to a zero angle at apogee, the light pressure acceleration in the x
direction is $ a_x = a_L sin( \omega t ) $ and $ a_y = a_L cos( \omega t ) $.
$ a_L $ is approximately 17 $ \mu m / s ^ 2 $ for a 100 micron thick server-sat.
Assuming we start at zero position and velocity,
then doubly integrating each of these equations results in $ x = ( a_L / \omega^2 ) ( \omega t - sin ( \omega t ) ) $
and $ y = ( a_L / \omega^2 ) ( 1 - cos ( \omega t ) ). This is the formula for a cycloid.
After one orbit period $P$ ( $\omega = 2 \pi / P $ ) x has shifted by $ a_0 P^2 / 2 \pi $.
The sum of these increments add up to the orbit circle over one year, so $ x * Year / P = 2 \pi \epsilon r_0 $.
Solving for the linear eccentricity, $ \epsilon r_0 = ( a_L P Year )/( (2 \pi)^2 $.
For $a_L$ = 17 \mu m / s ^ 2 $ and the m288 orbit ( P = 4*3600 = 14400 seconds ), this is around '''200 km'''.
|| Light Power || 1367 || watts ||
|| Speed of Light || 299,792,458 || m/s ||
|| Light pressure || 4.5598e-6 || kg/m-s^2 ||
||<-3> Server satellite params: ||
|| mass || 3e-3 || kg ||
|| thickness || 5e-5 || m ||
|| density || 2.654e+3 || kg/m^3 ^ ||
|| volume || 1.1303e-6 || m^3 ||
|| area || 2.2606e-2 || m^2 ||
|| force || 1.0308e-7 || kg-m/s^2 ||
|| acceleration || 3.436e-5 || m/s^2^ ||
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Lighter server-sats will have higher light pressure acceleration, and orbit with larger linear eccentricities. This will result in larger relative displacements. Regions of m288 with higher and lower server-sat area-to-mass ratios should be separated by hundreds or thousands of kilometers. == Light Pressure ==
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Perhaps the m360 and m480 orbits should be reserved for lighter and lighter server-sats, assuming that the trend over time will be towards lighter server-sats, better boosters, and more sophisticated latency management. Solar power arrays at lunar distances will be very light, but will have a lot more room for linear eccentricity displacements. {{{#!wiki caution
'''THE FOLLOWING ANALYSIS NEEDS FIXING.''' THE ANALYSIS BELOW IS INCORRECT because there is no $ \ddot x = k x $ force.

Light pressure increases apogee in the eastward orbital direction, decreases perigee in the west direction. The eclipse and J_2 and sun rotation perturbations must be made to match the light pressure perturbations, perhaps with some additional help from sideways thrust from non-perpendicular orientation.
}}}

I will show that for 3 gram 50 micron thick flat-sats in m288 orbits, the orbital perturbations from light pressure are small, 180 meters front to back oscillations along the line of the orbit at the spring and fall equinoxes, and 165 meters front to back at the summer and winter solstices. If the satellites get thinner, the perturbations increase proportional to the area to mass ratio. If the orbits move further out, the perturbations increase proportional to the cube of the orbit radius, because the orbit period grows, and the perturbations are proportional to the square of the orbit period. There is also a cumulative perturbation caused by the eclipse time, which is probably small enough to be corrected by optical maneuvering.

Previously I was not using the correct math for fictitious forces in a rotating frame. http://en.wikipedia.org/wiki/Rotating_frame has a good discussion, although they use $ \Omega $ where I use $ \omega_{m288} $. Their rotating frame does not include gravity, so the centrifugal force described here is stronger in the radial direction. Assume a circular orbit - toroidal orbits do not deviate much from that, and we can ignore Euler forces.

The fictitious forces are related to the radial and tangential position from mean perturbation center, and to the tangential velocity relative to that center.

An m288 orbit has the following parameters (subject to verification, please help me check them):

|| 3.986004418e14 m^3^/s^2^ || $ \mu_{\oplus} $ || Earth gravitational parameter ||
|| 23.439281&deg; || $ \phi $ || Earth axial tilt ||
|| 12,788,866 m || $ r_{m288} $ || m288 orbit radial distance ||
|| 80,354,815 m || || orbit circumference ||
|| 17,280 sec || || orbit period relative to Earth surface ||
|| 14,400 sec || || orbit period relative to Sun ||
|| 14,393.432 sec || $ T_{m288} $ || sidereal orbit period relative to stars ||
|| 5,582.7418 m/s || $ v_{m288} $ || orbital velocity ||
|| 2,290.7858 sec/rad || $ 1/\omega_{m288} $ || reciprocal of angular velocity ||
|| 4.3653142e-4 rad/sec || $ \omega_{m288} $ || angular velocity ||
|| 2.4371020 m/s^2^ || $ a_{m288} $ || gravitational force ||
|| 3.436e-5 m/s^2^ || $ a_{\lambda} $ || total light pressure acceleration @ 3g, 50$\mu$m glass ||
|| 180.3 m || $ \lambda $ || related light pressure displacement, see below ||
|| 0.161 || || Equinox eclipse fraction ||
|| 0.111 || || Solstice eclipse fraction ||

In a circular orbit, the centrifugal acceleration balances the centripedal gravitational acceleration:

$ v^2 / r = \omega^2 r = a = \mu_{\oplus} / r^2 ~ ~ ~ ~ = 2.4371020 m/s^2 $ at m288

$ \omega^2 = \mu_{\oplus} / r^3 $

If $ x \equiv $ the tangential distance forward of orbit center, then for small $ x $ the triangle of tangential and radial accelerations is proportional to the tangential and radial distances, from congruent triangles:

$ \partial a_x / a = - \partial x / r $

$ a_x = -( a / r ) x = - \omega^2 x $

With no perturbations, the vertical acceleration is:

$ a_r = \omega^2 ~ r - \mu_{\oplus} / r^2 = v^2 / r - \mu_{\oplus} / r^2 = 0 $

If the tangential velocity is perturbed, the radial acceleration is perturbed:

$ \partial a_r = 2 v / r \partial v_x = 2 \omega ~ \partial v_x $

If the radial distance is perturbed, the radial acceleration is also perturbed:

$ \partial a_r = ( \omega^2 + 2 \mu_{\oplus} / r^3 ) \partial r = 3 \omega^2 \partial r $

So the total radial acceleration, for small perturbations of $ y \equiv \Delta r $ and $ x $ is:

$ a_y = 3 \omega^2 ~ y + 2 \omega ~ v_x $

The radial and tangential accelerations are caused by the light pressure from the Sun. This can be divided into two components, the planar light pressure parallel to the plane and the light pressure perpendicular to the plane. These are a function of the time of year $ \beta $, and the Earth's axial tilt of $ \phi = $ 23.439281&deg; . We can compute the components from the cross product of the sunwards light pressure vector $ a_{\lambda} ~ \hat j $ and the normal vector of the equatorial plane given by $ \hat i = \sin( \phi ) \cos( \beta ) ~ $, $ ~ ~ \hat j = \sin( \phi ) \sin( \beta ) $, and $ \hat k = \cos ( \phi ) $. The perpendicular pressure is $ a_{\lambda ~ z} = a_{\lambda} \sin( \phi ) \sin( \beta ) $, and the planar pressure is $ a_{\lambda ~ p} = a_{\lambda} sqrt{ 1 - ( \sin( \phi ) \sin( \beta ) )^2 } $. At the equinoxes, $ a_{\lambda ~ z} = 0 $ and $ a_{\lambda ~ p} = a_{\lambda} $. At the solstices, $ a_{\lambda ~ z} = \pm a_{\lambda} \sin( \phi ) $ and $ a_{\lambda ~ p} = a_{\lambda} \cos( \phi ) $.

The perpendicular component does not change as the object orbits. The object is displaced above or below the equatorial plane by $ z ~ = ~ a_{\lambda ~ z} / \omega^2 ~ = ~ ( a_{\lambda} / { \omega^2 } ) \sin ( \phi ) \sin( \beta ) $. Define the parameter $ \lambda ~ \equiv ~ a_{\lambda} / { \omega^2 } = $ 180.3 meters for a 3 gram, 50 $\mu$m thick glass flat sat at m288 . The z displacement varies sinusoidally between $\pm$ 71.7 meters over the course of a year, far smaller than the cross section of the toroidal orbit.

$ \omega^2 = \mu_{\oplus} / r^3 $, so $ \lambda = a_{\lambda} r^3 / \mu_{\oplus} $. A thinner server satellite has higher $ a_{\lambda} $ and higher $ \lambda $. A more distant orbit also has higher $ \lambda $. For sufficiently thin satellites or large distances, the approximations above break down, and light pressure will push the satellites out of orbit, perhaps to escape velocity.

The planar light pressure makes one rotation per 14400 seconds around the guiding center, and is interrupted when the satellite is eclipsed by the Earth. We will compute the effect of this later. If we approximate the rotation as the sidereal period instead, and assume we can make up for eclipse and rotation changes by maneuvering (dangerous assumption), then we can approximate the light pressure components as:

$ a_{{\lambda} ~ y } = a_{\lambda ~ p} \sin( \omega t ) $

$ a_{{\lambda} ~ x } = - a_{\lambda ~ p } \cos( \omega t ) $

Assume that $ x = k \lambda \cos( \omega t ) ~ ~ $

Then $ ~ ~ ~ v_x = \dot { x } = - k \lambda \omega \sin( \omega t ) $

and $ ~ ~ ~ \ddot { x } = - k \lambda \omega^2 \cos( \omega t ) = - \omega^2 x $

The sum of the inertial force and the displacement force is equal to the light pressure:

$ - a_{\lambda ~ p } \cos( \omega t ) = \ddot { x } + a_x = - \omega^2 x + - \omega^2 x = -2 \omega^2 k \lambda \cos( \omega t ) $

Dividing both sides by $ \omega^2 \cos( \omega t ) $:

$ - a_{\lambda ~ p } / \omega^2 = \lambda = -2 k \lambda $. Thus, $ k = -0.5 $.

Therefore $ x = - 0.5 \lambda \cos( \omega t ) $ and $ v_x = - 0.5 a_{\lambda} / \omega \sin( \omega t ) $


The acceleration of y is the $ a_y $ fictitious force plus the light pressure:

$ \ddot{ y } = a_y + a_{{\lambda ~ p } ~ y } = 3 \omega^2 y + 2 \omega v_x + a_{\lambda ~ p} \sin( \omega t ) = 3 \omega^2 y + 2 \omega ( - a_{\lambda ~ p} / ( 2 \omega ) ) \sin( \omega t ) + a_{\lambda ~ p} \sin( \omega t ) = 3 \omega^2 y - a_{\lambda ~ p} \sin( \omega t ) + a_{\lambda ~ p} \sin( \omega t ) = 3 \omega^2 y $

If $ \ddot{ y } = 3 \omega^2 y $ , the only stable solution is $ y = 0 $ !!!


The satellite oscillates back and forth along the path of the orbit, but is not displaced radially by light pressure. The centrifugal acceleration of the tangential velocity exactly balances the light pressure.

== Perturbations because of eclipse ==

The above would be accurate if the earth was transparent. However, the satellite passes behind the earth for as much as 16.1% of its orbit during the equinoxes,
and 11.1% at the solstices.


MORE LATER

Light Pressure Modified Orbits

Light pressure effects modify server-sat array orbits. In the nominal orbit, server-sats are at "half thrust", with each thruster half mirror and half transparent. Variations to full or zero reflectivity, and full or zero thrust, allow each server-sat to maneuver in relation to the array, or for the array as a whole to maneuver around its assigned centerpoint. The following is an analysis of two effects, earth oblateness and nominal half-thrust light pressure, on the orbit. We will assume that the arrays maintain a constant, slightly elliptical orbit that precesses once per year in the equatorial plane. We will assume continuous illumination tangential to the equatorial plane, and zero light pressure effects from Earth albedo or black-body radiation, and no solar or lunar tides. These assumptions are somewhat crude approximations to get us into the ballpark of a solution. Precise solutions will probably demand accurate numerical solutions simulating many years of orbital evolution.

Earth Oblateness

For "heavy" server-sats relatively close to the earth, such as 3 gram satellites at m288, the dominant deviation from a perfect Kepler orbit is caused by the J_2 spherical harmonic of the gravity field, in turn caused by the oblateness of the spinning Earth. For small eccentricities, the eastward precession of the perigee of one elliptical equatorial orbit is proportional to the J_2 term of the WGS84 model ( -1.082626683E-03 , see Pisacane 2008 ) and the inverse of the orbit radius squared. The precession, expressed as the number complete precessions per year, is J \approx -3 J_2 ( Y / P ) ( R_e / R_s ) ^ 2 ~ ~ where

J

precessions per year caused by oblateness,

J_2

spherical harmonic of gravity causing oblateness,

Y

year period in seconds,

P

orbit period in seconds,

Y/P

number of orbits per year,

R_e

earth equatorial radius = 6378km,

R_s

orbit equatorial radius.

orbit

radius (RE)

orbits/year

J

LEO

1.047

5758.5

17.061

m288

2.005

2191.5

1.771

m360

2.264

1826.2

1.157

m480

2.627

1461.0

0.688

m720

3.182

1095.7

0.351

m1440

4.168

730.5

0.137

GEO

6.611

365.2

0.027

Server Satellite data

Light Power

1367

watts

Speed of Light

299,792,458

m/s

Light pressure

4.5598e-6

kg/m-s^2

Server satellite params:

mass

3e-3

kg

thickness

5e-5

m

density

2.654e+3

kg/m3

volume

1.1303e-6

m^3

area

2.2606e-2

m^2

force

1.0308e-7

kg-m/s^2

acceleration

3.436e-5

m/s2

Light Pressure

THE FOLLOWING ANALYSIS NEEDS FIXING. THE ANALYSIS BELOW IS INCORRECT because there is no $ \ddot x = k x $ force.

Light pressure increases apogee in the eastward orbital direction, decreases perigee in the west direction. The eclipse and J_2 and sun rotation perturbations must be made to match the light pressure perturbations, perhaps with some additional help from sideways thrust from non-perpendicular orientation.

I will show that for 3 gram 50 micron thick flat-sats in m288 orbits, the orbital perturbations from light pressure are small, 180 meters front to back oscillations along the line of the orbit at the spring and fall equinoxes, and 165 meters front to back at the summer and winter solstices. If the satellites get thinner, the perturbations increase proportional to the area to mass ratio. If the orbits move further out, the perturbations increase proportional to the cube of the orbit radius, because the orbit period grows, and the perturbations are proportional to the square of the orbit period. There is also a cumulative perturbation caused by the eclipse time, which is probably small enough to be corrected by optical maneuvering.

Previously I was not using the correct math for fictitious forces in a rotating frame. http://en.wikipedia.org/wiki/Rotating_frame has a good discussion, although they use \Omega where I use \omega_{m288} . Their rotating frame does not include gravity, so the centrifugal force described here is stronger in the radial direction. Assume a circular orbit - toroidal orbits do not deviate much from that, and we can ignore Euler forces.

The fictitious forces are related to the radial and tangential position from mean perturbation center, and to the tangential velocity relative to that center.

An m288 orbit has the following parameters (subject to verification, please help me check them):

3.986004418e14 m3/s2

\mu_{\oplus}

Earth gravitational parameter

23.439281°

\phi

Earth axial tilt

12,788,866 m

r_{m288}

m288 orbit radial distance

80,354,815 m

orbit circumference

17,280 sec

orbit period relative to Earth surface

14,400 sec

orbit period relative to Sun

14,393.432 sec

T_{m288}

sidereal orbit period relative to stars

5,582.7418 m/s

v_{m288}

orbital velocity

2,290.7858 sec/rad

1/\omega_{m288}

reciprocal of angular velocity

4.3653142e-4 rad/sec

\omega_{m288}

angular velocity

2.4371020 m/s2

a_{m288}

gravitational force

3.436e-5 m/s2

a_{\lambda}

total light pressure acceleration @ 3g, 50\mum glass

180.3 m

\lambda

related light pressure displacement, see below

0.161

Equinox eclipse fraction

0.111

Solstice eclipse fraction

In a circular orbit, the centrifugal acceleration balances the centripedal gravitational acceleration:

v^2 / r = \omega^2 r = a = \mu_{\oplus} / r^2 ~ ~ ~ ~ = 2.4371020 m/s^2 at m288

\omega^2 = \mu_{\oplus} / r^3

If x \equiv the tangential distance forward of orbit center, then for small x the triangle of tangential and radial accelerations is proportional to the tangential and radial distances, from congruent triangles:

\partial a_x / a = - \partial x / r

a_x = -( a / r ) x = - \omega^2 x

With no perturbations, the vertical acceleration is:

a_r = \omega^2 ~ r - \mu_{\oplus} / r^2 = v^2 / r - \mu_{\oplus} / r^2 = 0

If the tangential velocity is perturbed, the radial acceleration is perturbed:

\partial a_r = 2 v / r \partial v_x = 2 \omega ~ \partial v_x

If the radial distance is perturbed, the radial acceleration is also perturbed:

\partial a_r = ( \omega^2 + 2 \mu_{\oplus} / r^3 ) \partial r = 3 \omega^2 \partial r

So the total radial acceleration, for small perturbations of y \equiv \Delta r and x is:

a_y = 3 \omega^2 ~ y + 2 \omega ~ v_x

The radial and tangential accelerations are caused by the light pressure from the Sun. This can be divided into two components, the planar light pressure parallel to the plane and the light pressure perpendicular to the plane. These are a function of the time of year \beta , and the Earth's axial tilt of \phi = 23.439281° . We can compute the components from the cross product of the sunwards light pressure vector a_{\lambda} ~ \hat j and the normal vector of the equatorial plane given by \hat i = \sin( \phi ) \cos( \beta ) ~ , ~ ~ \hat j = \sin( \phi ) \sin( \beta ) , and \hat k = \cos ( \phi ) . The perpendicular pressure is a_{\lambda ~ z} = a_{\lambda} \sin( \phi ) \sin( \beta ) , and the planar pressure is a_{\lambda ~ p} = a_{\lambda} sqrt{ 1 - ( \sin( \phi ) \sin( \beta ) )^2 } . At the equinoxes, a_{\lambda ~ z} = 0 and a_{\lambda ~ p} = a_{\lambda} . At the solstices, a_{\lambda ~ z} = \pm a_{\lambda} \sin( \phi ) and a_{\lambda ~ p} = a_{\lambda} \cos( \phi ) .

The perpendicular component does not change as the object orbits. The object is displaced above or below the equatorial plane by z ~ = ~ a_{\lambda ~ z} / \omega^2 ~ = ~ ( a_{\lambda} / { \omega^2 } ) \sin ( \phi ) \sin( \beta ) . Define the parameter \lambda ~ \equiv ~ a_{\lambda} / { \omega^2 } = 180.3 meters for a 3 gram, 50 \mum thick glass flat sat at m288 . The z displacement varies sinusoidally between \pm 71.7 meters over the course of a year, far smaller than the cross section of the toroidal orbit.

\omega^2 = \mu_{\oplus} / r^3 , so \lambda = a_{\lambda} r^3 / \mu_{\oplus} . A thinner server satellite has higher a_{\lambda} and higher \lambda . A more distant orbit also has higher \lambda . For sufficiently thin satellites or large distances, the approximations above break down, and light pressure will push the satellites out of orbit, perhaps to escape velocity.

The planar light pressure makes one rotation per 14400 seconds around the guiding center, and is interrupted when the satellite is eclipsed by the Earth. We will compute the effect of this later. If we approximate the rotation as the sidereal period instead, and assume we can make up for eclipse and rotation changes by maneuvering (dangerous assumption), then we can approximate the light pressure components as:

a_{{\lambda} ~ y } = a_{\lambda ~ p} \sin( \omega t )

a_{{\lambda} ~ x } = - a_{\lambda ~ p } \cos( \omega t )

Assume that x = k \lambda \cos( \omega t ) ~ ~

Then ~ ~ ~ v_x = \dot { x } = - k \lambda \omega \sin( \omega t )

and ~ ~ ~ \ddot { x } = - k \lambda \omega^2 \cos( \omega t ) = - \omega^2 x

The sum of the inertial force and the displacement force is equal to the light pressure:

- a_{\lambda ~ p } \cos( \omega t ) = \ddot { x } + a_x = - \omega^2 x + - \omega^2 x = -2 \omega^2 k \lambda \cos( \omega t )

Dividing both sides by \omega^2 \cos( \omega t ) :

- a_{\lambda ~ p } / \omega^2 = \lambda = -2 k \lambda . Thus, k = -0.5 .

Therefore x = - 0.5 \lambda \cos( \omega t ) and v_x = - 0.5 a_{\lambda} / \omega \sin( \omega t )

The acceleration of y is the a_y fictitious force plus the light pressure:

\ddot{ y } = a_y + a_{{\lambda ~ p } ~ y } = 3 \omega^2 y + 2 \omega v_x + a_{\lambda ~ p} \sin( \omega t ) = 3 \omega^2 y + 2 \omega ( - a_{\lambda ~ p} / ( 2 \omega ) ) \sin( \omega t ) + a_{\lambda ~ p} \sin( \omega t ) = 3 \omega^2 y - a_{\lambda ~ p} \sin( \omega t ) + a_{\lambda ~ p} \sin( \omega t ) = 3 \omega^2 y

If \ddot{ y } = 3 \omega^2 y , the only stable solution is y = 0 !!!

The satellite oscillates back and forth along the path of the orbit, but is not displaced radially by light pressure. The centrifugal acceleration of the tangential velocity exactly balances the light pressure.

Perturbations because of eclipse

The above would be accurate if the earth was transparent. However, the satellite passes behind the earth for as much as 16.1% of its orbit during the equinoxes, and 11.1% at the solstices.

MORE LATER

LightOrbit (last edited 2024-02-20 03:54:20 by KeithLofstrom)