|
Size: 1214
Comment:
|
Size: 1122
Comment: 4
|
| Deletions are marked like this. | Additions are marked like this. |
| Line 4: | Line 4: |
| Thinsat displacement distance versus time is approximately $ 0.1 a^2 $, where $ a $ is the peak acceleration from light pressure. If the peak acceleration is 20 microns per second squared, then a thinsat can maneuver these distances in the given period of time: | Thinsat displacement distance versus time is approximately 4 microns per second squared. A thinsat can maneuver these distances in the given period of time: |
| Line 6: | Line 6: |
| || time || distance || degrees of orbit || || 1 second || 2 microns || || || 1 minute || 7 millimeters || || || 5 minutes || 18 centimeters || || || 20 minutes || 3 meters || || || 1 hour || 26 meters || || || 4 hours || 400 meters || || || 24 hours || 15 kilometers || 0.07 degrees || |
|| time || accelerate || move and stop || degrees of orbit || || 1 second || 1 micron || || || 1 minute || 4 millimeters || || || 5 minutes || 36 centimeters || || || 20 minutes || 6 meters || || || 1 hour || 52 meters || || || 4 hours || 800 meters || || || 24 hours || 30 kilometers || 0.14 degrees || |
Local Maneuvering
Thinsat displacement distance versus time is approximately 4 microns per second squared. A thinsat can maneuver these distances in the given period of time:
time |
accelerate |
move and stop |
degrees of orbit |
1 second |
1 micron |
|
|
1 minute |
4 millimeters |
|
|
5 minutes |
36 centimeters |
|
|
20 minutes |
6 meters |
|
|
1 hour |
52 meters |
|
|
4 hours |
800 meters |
|
|
24 hours |
30 kilometers |
0.14 degrees |
|
3 days |
135 kilometers |
0.6 degrees |
|
1 week |
730 kilometers |
3.3 degrees |
|
1 month |
14K kilometers |
63 degrees |
|
52 days |
40K kilometers |
180 degrees |
If the wavelength is 8mm and the ground antenna is 500mm across, the aperture is about 0.5 degrees. So, in 3 days a thinsat can move from one aperture to the next, and in 52 days it can move anywhere in the m288 orbit.