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Given apogee $ r_a $ and perigee $ r_p $ and $ \mu_e = $ 3.986e14 m^3 /s^2 and angle from perigee, true anomaly: $ \Large \theta $ Given apogee $ r_a $ and perigee $ r_p $ and $ \mu_e = $ 3.986e14 m^3^/s^2^ and angle from perigee, true anomaly: $ \Large \theta $
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( note: $a$ is more commonly used for the semimajor axis. I use $s$ to avoid confusion with apogee )

Perigee Drag

Approximating the drag on a decaying transfer orbit


What is the velocity and radius versus time for an elliptical orbit?

Given apogee r_a and perigee r_p and \mu_e = 3.986e14 m3/s2 and angle from perigee, true anomaly: \Large \theta

eccentricity: \large e = ( r_a - r_p ) / ( r_a + r_p )

semimajor axis: \large s = ( r_a + r_p ) / 2

characteristic velocity: \large v_0 = \LARGE\sqrt{{\mu \over 2}\left({1 \over r_a}+{1 \over r_p}\right)}

eccentric anomaly (ellipse center angle): \large E=\arccos\Large\left({{e+\cos(\theta)}\over{1+e\cos(\theta)}}\right)

mean anomaly: \large M = E - e \sin( E )

time from perigee: \large t = M / \omega

radius: \large r=s\Large{{1-e^2}\over{1+e\cos(\theta)}}

perigee radius: \large r_p =( 1-e ) s

perpendicular velocity: \large v_{\perp}= v_0 ( 1+e \cos( \theta ))

perigee velocity: \large v_p =(1+e)v_0

total velocity, tangent to orbit: \Large v=\LARGE \sqrt{{{2\mu}\over{r}}-{{\mu}\over{a}}}

angular momentum: \large L =\LARGE \sqrt{ { 2 \mu ~ r_a ~ r_p } \over { r_a + r_p } }

( note: a is more commonly used for the semimajor axis. I use s to avoid confusion with apogee )

PerigeeDrag (last edited 2016-09-18 19:27:12 by KeithLofstrom)