Reentry
Assume everything goes wrong, and all the thinsats eventually fall into the atmosphere. They will likely be tumbling, slowly or quickly, and perhaps they will shatter. What will re-entry be like?
Assume the perpendicular from a round fragment can point in any direction. Either the front or the back is "shining" in the direction of motion, so there is 2 \pi R ^ 2 area, and that area can be "expressed" in 4 \pi steradians different directions. So we can assume that the average area facing forwards during tumble is half the total area. We can compute the ballistic coefficient by doubling the thickness: A 50 micron thick glass thinsat will have a ballistic coefficient of 2650*2*5E-5 = 0.265 Kg/m2.
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