Size: 1203
Comment:
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Size: 1203
Comment:
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Deletions are marked like this. | Additions are marked like this. |
Line 9: | Line 9: |
|| Height ||<:-2> $ B = \sqrt{3} C / 2 = \sqrt{3\sqrt{A}} $ || || | || Height ||<:-2> $ B = (\sqrt{3}/2) C = \sqrt{\sqrt{3}A} $ || || |
Triangle or Square?
What is the optimum shape for a thinsat?
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Triangle |
Square |
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Area |
A = \sqrt{3} C^2 / 4 |
A = Q^2 |
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Side |
C = 2 \sqrt{A / \sqrt{3} } |
Q = \sqrt{A} |
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Height |
B = (\sqrt{3}/2) C = \sqrt{\sqrt{3}A} |
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Ratio |
C = ( 2 /\sqrt[4]{3} ) Q ~ \approx ~ 1.51967 ~ Q |
Q = ( \sqrt[4]{3}/2 ) C ~ \approx ~ 0.65804 ~ C |
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Rotational |
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Moment of |
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Torque T |
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Angular |
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