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|| Ratio ||<:-2> $ T = ( 2 /\sqrt[4]{3} ) Q $ ||<:-2> $ Q = ( \sqrt[4]{3}/2 ) T $ ||

Triangle or Square?

What is the optimum shape for a thinsat?


Triangle

Square

Tri.png

Quad.png

Area

A = \sqrt{3} T^2 / 4

A = Q^2

Side

T = 2 \sqrt{A / \sqrt{3} }

Q = \sqrt{A}

Ratio

T = ( 2 /\sqrt[4]{3} ) Q

Q = ( \sqrt[4]{3}/2 ) T

Rotational
Center

TriA.png

TriB.png

QuadA.png

QuadB.png

Moment
of
Inertia

TriQuad (last edited 2015-07-18 07:25:18 by KeithLofstrom)